|
|||||||||||||||||||||||||||||||||
AMBER Archive (2007)Subject: AMBER: equilibrium constants via MMPBSA
From: Sean Rathlef (sean_at_syncitium.net)
Dear Amber,
A quick question regarding Keq computations via MMPBSA. I have an association reaction (A + B --> AB). I am modeling the free energies for AB, A, and B, and generating my deltaG from:
1 delG(AB) - [delG(A) + delgG(B)].
Keq is then computed via:
2 Keq = e^(-delG/RT).
In this instance, Keq will have units of M-1, because of the relationship to the concetrations of the species, i.e.,
3 Keq = [AB] / [A]*[B]
The Keq leveraged from equation 2 however is unitless, so would it be appropriate to simply divide this value by standard state concentraion, C_0, of 1M?
Thanks for any responses,
-----------------------------------------------------------------------
| |||||||||||||||||||||||||||||||||
|