| 
  |||||||||||||||||||||||||||||||||
AMBER Archive (2007)Subject: AMBER: equilibrium constants via MMPBSA
From: Sean Rathlef (sean_at_syncitium.net) 
 
 
 
Dear Amber,
 A quick question regarding Keq computations via MMPBSA.  I have an association reaction (A + B --> AB).  I am modeling the free energies for AB, A, and B, and generating my deltaG from: 
 1    delG(AB) - [delG(A) + delgG(B)].  
 Keq is then computed via:
 2    Keq = e^(-delG/RT).
 In this instance, Keq will have units of M-1, because of the relationship to the concetrations of the species, i.e., 
 3    Keq = [AB] / [A]*[B]
 The Keq leveraged from equation 2 however is unitless, so would it be appropriate to simply divide this value by standard state concentraion, C_0, of 1M?
 Thanks for any responses,
 -----------------------------------------------------------------------
 
 
  | |||||||||||||||||||||||||||||||||
	
  | 
|||||||||||||||||||||||||||||||||