AMBER Archive (2007)Subject: RE: AMBER: ADDIONS do not neutralize to ZERO
From: Bill Ross (ross_at_cgl.ucsf.edu) 
Date: Tue Jan 23 2007 - 11:30:06 CST
 
 
 
 
> I have an organic ligand for which the charge is >>>
 
> 
 
> > check TEL
 
> Checking 'TEL'....
 
> WARNING: The unperturbed charge of the unit: 0.999960 is not zero.
 
> Checking parameters for unit 'TEL'.
 
> Checking for bond parameters.
 
> Checking for angle parameters.
 
> check:  Warnings: 1
 
> Unit is OK.
 
> 
 
> Should this be a problem? I want to simulate the system with the
 
> organic ligand charged.
 
 I forget if there's a 'fudge factor' when neutralizing with ions.
 
This is pretty close to integral charge. If you can get it to 1.0
 
that could neutralize worry :-) If you don't want to neutralize it
 
with an ion, I doubt it's a problem. Otherwise try and see if it 
 
gets neutralized.
 
 Bill
 
 > 
 
> Thanks for help. Best Regards
 
> Akshay Patny (Olemiss)
 
> 
 
> = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =
 
> Akshay Patny
 
> PhD Candidate (5th Yr.), Computational Chemistry
 
> Department of Medicinal Chemistry, School of Pharmacy
 
> The University of Mississippi
 
> 805 College Hill Rd, # 9, Oxford, MS 38655
 
> E-mail: akshay17_at_olemiss.edu
 
> Phone (O): (662)-915-1286,(M): (662)-801-5496
 
> = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =
 
> 
 
> -----Original Message-----
 
> From: owner-amber_at_scripps.edu [mailto:owner-amber_at_scripps.edu] On
 
> Behalf Of Bill Ross
 
> Sent: Monday, January 22, 2007 7:58 PM
 
> To: amber_at_scripps.edu
 
> Subject: Re: AMBER: ADDIONS do not neutralize to ZERO
 
> 
 
> >> addions2 ang Cl- 0
 
> > ERROR: The unperturbed charge of the unit: 0.970410 is not integral.
 
> > WARNING: The unperturbed charge of the unit: 0.970410 is not zero.
 
> 
 
> > I defined in my command to neutralize the system until the charge
 
> > becomes '0'. Can you suggest me what is going wrong, or if it is
 
> > okay??
 
> 
 
> If you were to 'check ang' before adding ions, the charge would
 
> presumably not be integral, e.g. .97041 after the decimal. Do you
 
> have any non-standard residues that might have a non-integral
 
> charge? Leap adds ions with integral charge and thus the solute
 
> must have integral charge to arrive at 0.
 
> 
 
> Bill
 
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