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AMBER Archive (2002)Subject: simulated annealing example
From: Snyder, James (zyu4_at_cdc.gov)
Greetings:
I am attempting to run a simulated annealing calc. using the sample input
???????
Thank You,
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| Wed Jul 10 16:17:53 2002
[-O]verwriting output
File Assignments:
| MDOUT: 1fv1_sa.out
|INPCRD: 1fv1_sa.crd
| PARM: 1fv1_sa.top
|RESTRT: 1fv1_sa.rst
| REFC: 1fv1_sa.crd
| MDVEL: mdvel
| MDEN: mden
| MDCRD: 1fv1_sa.traj
|MDINFO: mdinfo
|INPDIP: inpdip
|RSTDIP: rstdip
&cntrl
nstlim=15000, ntt=1, (time limit, temp. control)
scee=1.2, (scee holds the 1-4 scale factor)
ntpr=500, pencut=0.1, (control of printout)
ipnlty=1, nmropt=1, (NMR penalty function options)
vlimit=10, (prevent bad temp. jumps)
ntb=0, (non-periodic simulation)
&end
#
# Simple simulated annealing algorithm:
#
# from steps 0 to 1000: raise target temperature 10->1200K
# from steps 1000 to 3000: leave at 1200K
# from steps 3000 to 15000: re-cool to low temperatures
#
&wt type='TEMP0', istep1=0,istep2=1000,value1=10.,
value2=1200., &end
&wt type='TEMP0', istep1=1001, istep2=3000, value1=1200.,
value2=1200.0, &end
&wt type='TEMP0', istep1=3001, istep2=15000, value1=0.,
value2=0.0, &end
#
# Strength of temperature coupling:
#
# steps 0 to 3000: tight coupling for heating and equilibration
# steps 3000 to 11000: slow cooling phase
# steps 11000 to 13000: somewhat faster cooling
# steps 13000 to 15000: fast cooling, like a minimization
#
&wt type='TAUTP', istep1=0,istep2=3000,value1=0.2,
value2=0.2, &end
&wt type='TAUTP', istep1=3001,istep2=11000,value1=4.0,
value2=2.0, &end
&wt type='TAUTP', istep1=11001,istep2=13000,value1=1.0,
value2=1.0, &end
&wt type='TAUTP', istep1=13001,istep2=14000,value1=0.5,
value2=0.5, &end
&wt type='TAUTP', istep1=14001,istep2=15000,value1=0.05,
value2=0.05, &end
#
# "Ramp up" the restraints over the first 3000 steps:
#
&wt type='REST', istep1=0,istep2=3000,value1=0.1,
value2=1.0, &end
&wt type='REST', istep1=3001,istep2=15000,value1=1.0,
value2=1.0, &end
&wt type='END' &end
LISTOUT=POUT
DISANG=RST.f
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